drop-down navigation menu with HTML PHP MySQL

EDIT FIXED by user @jeroen You have to move the li and a tags inside the while loop.

Thank you for this, F4LLCON

So the final code (not so clean, but works now):

<?php   

$query = mysql_query("SELECT * FROM `apps` ");

while ($query_row = mysql_fetch_assoc($query))

{

?>

<li><a href="">

<?php

echo $query_row['TITLE'];

?>

</a>

</li>

<br />

<?php

}

?>

I want a drop-down menu that will show the TITLES out of my MySQL database. I know how to do everything concerning the ID etc.

The only problem is that the PHP version of the drop-down menu will SELECT all the TITLES in my database and parse it as ONE link.

So instead of

Home

>About

>Contact

>Another

it will look like

Home

>About

 Contact

 Another

With other words

Home

>About Contact Another

It will not make multiple drop-down links but only one drop-down link

If you for example do:

<div>

<?php

echo $query_row['TITLE'];

?>

</div>

It will make a individual <div></div> for every TITLE in my database, so I thought this method would also work for the drop-down links..

Does anybody know how to fix it so it will make individual <li></li> for every TITLE?

Here is a normal drop-down menu:

<li id="media"><a href=""></a> 

    <ul>

    <li id="1a"><a href="">About</a></li> 

    <li id="1b"><a href="">Contact</a></li> 

    <li id="1b"><a href="">Another</a></li> 

    </ul>

</li>

And here is the PHP drop-down menu:

<li id="media"><a href=""></a> 

<ul>

<li>

<a href="">

<?php   

$query = mysql_query("SELECT * FROM `apps` ");

while ($query_row = mysql_fetch_assoc($query))

{

echo $query_row['TITLE'];

?>

<br />

<?php

}

?>

</a>

</li>

</ul>

</li>