Fastest way to determine if an integer"s square root is an integer

I'm looking for the fastest way to determine if a long value is a perfect square (i.e. its square root is another integer). I've done it the easy way, by using the built-in Math.sqrt() function, but I'm wondering if there is a way to do it faster by restricting yourself to integer-only domain. Maintaining a lookup table is impratical (since there are about 2 ^31.5 integers whose square is less than 2 ⁶³ ).