Can I call die after echo with PHP?

Thursday, May 10, 2012

I'm trying to add some error checking inside my PHP script. Is it valid to do this:




if (!mkdir($dir, 0)) {

    $res->success = false;

    $res->error = 'Failed to create directory';

    echo json_encode($res);

    die;

}

Is there a better way to exit the script after encountering an error like this?

UserMay 10, 2012 at 9:39 PM
That looks fine to me.

You can even echo data in the die like so:

if (!mkdir($dir, 0)) {
$res->success = false;
$res->error = 'Failed to create directory';
die(json_encode($res));
}
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UserMay 10, 2012 at 9:39 PM
Throwing a exception. Put code into a try catch block, and throw exception when you need.
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UserMay 10, 2012 at 9:39 PM
PHP has functions for error triggering and handling.

if (!mkdir($dir, 0)) {
trigger_error('Failed to create directory', E_USER_ERROR)
}

When you do this the script will end. The message will be written to the configured error log and it will also be displayed when error_reporting is enabled.
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